How do you simplify $(4 + \sqrt{8}) (4 - \sqrt{8})$ $(4+ sqrt8)(4- sqrt8)$ ?

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Answer 1 · 2016-08-22T17:25:25

$= 8$ $=8$

$(a + b) (a - b) = a^{2} - b^{2}$ $(a+b)(a-b)=a^2-b^2$

Similarly

$(4 + \sqrt{8}) (4 - \sqrt{8})$ $(4+sqrt8)(4-sqrt8)$

$= 4^{2} - {(\sqrt{8})}^{2}$ $=4^2-(sqrt8)^2$

$= 16 - 8$ $=16-8$

$= 8$ $=8$

How do you simplify (4+√8)(4−√8)(4+ sqrt8)(4- sqrt8)?