How do you simplify #4*sqrt20 - *sqrt45 + 7*sqrt5#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Steve J. May 27, 2018 #12*sqrt(5)# Explanation: #4*sqrt(20) - sqrt(45)+7*sqrt(5)# Simplifying #4*sqrt(5*4) - sqrt(5*9)+7*sqrt(5)# #4*2*sqrt(5) - 3*sqrt(5)+7*sqrt(5)# #8*sqrt(5) - 3*sqrt(5)+7*sqrt(5) = 12*sqrt(5)# I hope this hekos, Steve Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1391 views around the world You can reuse this answer Creative Commons License