How do you simplify $\frac{- 4 \sqrt{6}}{\sqrt{27}}$ $(-4 sqrt(6)) / sqrt(27)$ ?

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How do you simplify $\frac{- 4 \sqrt{6}}{\sqrt{27}}$ $(-4 sqrt(6)) / sqrt(27)$ ?

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Answer 1 · 2016-09-04T14:29:23

$\frac{4 \sqrt{6}}{\sqrt{27}}$ $(4sqrt(6))/sqrt27$ $=$ $=$ $\frac{- 4 \sqrt{2}}{3}$ $(-4sqrt2)/3$

Explanation:

$\frac{4 \sqrt{6}}{\sqrt{27}}$ $(4sqrt(6))/sqrt27$ $=$ $=$ $(-4sqrt(2)xxcancelsqrt(3))/(sqrt(9)xxcancelsqrt3)$ $=$ $(-4sqrt(2))/sqrt(9)$ $=$ $(-4sqrt2)/3$

So in effect, you factorize the square roots.

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How do you simplify $\frac{- 4 \sqrt{6}}{\sqrt{27}}$ $(-4 sqrt(6)) / sqrt(27)$ ?

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How do you simplify $\frac{- 4 \sqrt{6}}{\sqrt{27}}$ $(-4 sqrt(6)) / sqrt(27)$ ?