How do you simplify #4^(log_2 [log_ 2(x^2+24x))]#?

1 Answer
Gió
Jun 17, 2016

This is the best I got:

Explanation:

I tried writing #4# as #2*2#:
#(2*2)^(log_2[log_2(x^2+24x)])=2^(log_2[log_2(x^2+24x)])*2^(log_2[log_2(x^2+24x)])=#
And:
#=cancel(2)^(cancel(log_2)[log_2(x^2+24x)])*cancel(2)^(cancel(log_2)[log_2(x^2+24x)])=#
#=log_2(x^2+24x)log_2(x^2+24x)#

Related questions
See all questions in Common Logs
Impact of this question
1162 views around the world
You can reuse this answer
Creative Commons License