How do you simplify $(3y^3)^3(4y^2)^-3$ and write it using only positive exponents?

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Answer 1 · 2017-07-24T02:06:15

See below.

Let's take each expression separately.

$(3y^3)^3=27y^9$

$(4y^2)^-3=1/64y^-6=1/(64y^6)$

Multiplying,

$27y^9\cdot1/(64y^6)=27/64\cdoty^9/y^6=27/64y^3$

How do you simplify (3y^3)^3(4y^2)^-3(3y^3)^3(4y^2)^-3 and write it using only positive exponents?