How do you simplify #(3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)#?

1 Answer
Acquaintance
Jul 8, 2016

#(9y^4)/(4x^7)#

Explanation:

remember:

#a^b * a^c = a^(b+c)#

work

#(3xy^4)/(2x^5y) * (6x^-3y^2)/(4y)#

Simplify by dividing out factors in the top and bottom

#(3y^3)/(2x^4) * (3x^-3y)/(2)#

Now change the #x^-3# into #1/x^3# and bring it into the denominator since anything to a negative power is one over that number to the positive exponent

#(3y^3)/(2x^4) * (3y)/(2x^3)#

Now we can multiply

#(3y^3times3y)/(2x^4times2x^3)#

And simplify

#(9y^4)/(4x^7)#

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