How do you simplify ${(3 x^{4})}^{3}$ $(3x^4)^3$ ?

Question

5839 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-02T21:07:11

$27 x^{12}$ $27x^12$

The indices rule for this scenario is that

${(x^{a})}^{b} = x^{a b}$ $(x^a)^b = x^(ab)$

Removing the '3' from the bracket gives:

${(3)}^{3} {(x^{4})}^{3}$ $(3)^3(x^4)^3$

which resolves to

$27 x^{12}$ $27x^12$

How do you simplify (3x4)3(3x^4)^3?