How do you simplify #(3sqrt6+2sqrt5) /( sqrt6+sqrt 5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Cesareo R. May 31, 2016 #8-sqrt(30)# Explanation: Using #(a+b)(a-b)=a^2-b^2# and simplifying #(3 sqrt[6] + 2 sqrt[5])/(sqrt[6] + sqrt[5]) =((3 sqrt[6] + 2 sqrt[5]) (sqrt[6] - sqrt[5]))/((sqrt[6] + sqrt[5]) (sqrt[6] - sqrt[5])) = 8 -sqrt(30)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1050 views around the world You can reuse this answer Creative Commons License