How do you simplify #(3sqrt6+2sqrt5) /( sqrt6+sqrt 5)#?

Question

How do you simplify #(3sqrt6+2sqrt5) /( sqrt6+sqrt 5)#?

1 Answer

Impact of this question

1117 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-31T12:03:09

#8-sqrt(30)#

Explanation:

Using #(a+b)(a-b)=a^2-b^2# and simplifying
#(3 sqrt[6] + 2 sqrt[5])/(sqrt[6] + sqrt[5]) =((3 sqrt[6] + 2 sqrt[5]) (sqrt[6] - sqrt[5]))/((sqrt[6] + sqrt[5]) (sqrt[6] - sqrt[5])) = 8 -sqrt(30)#

Science

Math

Humanities

... and beyond

How do you simplify #(3sqrt6+2sqrt5) /( sqrt6+sqrt 5)#?

1 Answer

Explanation:

Related questions

Impact of this question