How do you simplify #(3sqrt5)/sqrt7#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Andrew012p Mar 4, 2018 # (3sqrt35)/7# Explanation: Given expression, #(3sqrt(5))/sqrt7# We get, #(3sqrt(5))/sqrt7 * sqrt7/sqrt7 = (3sqrt5*sqrt(7))/(sqrt7)^2= (3sqrt35)/7# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1214 views around the world You can reuse this answer Creative Commons License