How do you simplify #(3sqrt5)/64#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Monzur R. Jun 6, 2017 It cannot be simplified any further. Explanation: #64# is not a multiple of #3#, so we cannot cancel any factors in the fraction and #sqrt5# is irrational, meaning that if we were to write it out, we wouldn't it out, we wouldn't find any recurring patterns. As such, we can't simplify it either. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 862 views around the world You can reuse this answer Creative Commons License