How do you simplify #(3sqrt20)/(2sqrt4)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Lithia Feb 16, 2017 #(3sqrt(5))/2# Explanation: to simplify #(3sqrt(20))/(2sqrt(4))# you need to rationalize the denominator which means you need to get rid of that square root in the denominator fortunately #sqrt(4) = 2# so simplifying this expression is easy #(3sqrt(20))/(2sqrt(4)) = (3sqrt(20))/(2*2) = (3sqrt(20))/4# and #sqrt(20) = 2sqrt(5)# #(3sqrt(20))/4 = (3*2sqrt(5))/4 = (6sqrt(5))/4 = (3sqrt(5))/2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1582 views around the world You can reuse this answer Creative Commons License