How do you simplify #3sqrt(y^4)* 3sqrt(81y^5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer MathFact-orials.blogspot.com Apr 15, 2017 #81y^4sqrty=81y^(9/2)# Explanation: We can rewrite: #3sqrt(y^4)xx3sqrt(81y^5)=># #3xxsqrt(y^2)xxsqrt(y^2)xx3xxsqrt81xxsqrt(y^2)xxsqrt(y^2)xxsqrty=># #3xx3xxsqrt(9^2)xxsqrt(y^2)xxsqrt(y^2)xxsqrt(y^2)xxsqrt(y^2)xxsqrty=># #9xx9xxyxxyxxyxxyxxsqrty=># #81y^4sqrty=81y^(9/2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 841 views around the world You can reuse this answer Creative Commons License