How do you simplify #3sqrt ((8x^8)/(y^3))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Jun 5, 2016 #(6x^2sqrt(2y))/y# Explanation: Write as:#" "3xxsqrt(2^2xx2xx (x^2)^4)/sqrt(y^2xxy)# #=(3xx2xxx^4)/y xx sqrt(2)/sqrt(y)# #=(6x^4sqrt(2))/sqrt(y)# Multiply by 1 but in the form of #1=sqrt(y)/sqrt(y)# #=(6x^2sqrt2sqrty)/y# #(6x^2sqrt(2y))/y# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 881 views around the world You can reuse this answer Creative Commons License