How do you simplify $(-3r^2s^-4)(2r^-3s^7)^2$ ?

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How do you simplify $(-3r^2s^-4)(2r^-3s^7)^2$ ?

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Answer 1 · 2018-06-20T11:32:23

$color(indigo)(=> -12 r^-4 * s^10 = (-12 s^10)/r^4$

Explanation:

![http://quantbasics.blogspot.com/2010/04/http://indices-and-surds.html](https://useruploads.socratic.org/AAJCnfJYRLOF0YhMuGcR_theory%20of%20indices.jpg)

$(-3 r^2 s^-4)((2r^-3s^7)^2$

$=> (-3 r^2 s^-4) (2^2 r^-6 s^14)$

$=> (-3 * 4 * r^2 * r^-6 * s^-4 * s^14)$

$color(indigo)(=> -12 r^-4 * s^10 = (-12 s^10)/r^4$

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How do you simplify $(-3r^2s^-4)(2r^-3s^7)^2$ ?

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How do you simplify (-3r^2s^-4)(2r^-3s^7)^2(-3r^2s^-4)(2r^-3s^7)^2?

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How do you simplify $(-3r^2s^-4)(2r^-3s^7)^2$ ?