How do you simplify $\frac{3 q + 2}{2 q + 1} + \frac{q - 5}{2 q + 1}$ $(3q+2)/(2q+1)+(q-5)/(2q+1)$ ?

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Answer 1 · 2017-02-01T11:44:38

See the entire simplification process below:

Because both fractions have a common denominator we can add the numerators by rewriting this equation as:

$\frac{3 q + 2 + q - 5}{2 q + 1}$ $(3q + 2 + q - 5)/(2q + 1)$

Next, group and combine common terms in the numerator:

$\frac{3 q + q + 2 - 5}{2 q + 1} \to \frac{3 q + 1 q + 2 - 5}{2 q + 1} \to$ $(3q + q + 2 - 5)/(2q + 1) -> (3q + 1q + 2 - 5)/(2q + 1) ->$

$\frac{(3 + 1) q - 3}{2 q + 1} \to$ $((3 + 1)q - 3)/(2q + 1) ->$

$\frac{4 q - 3}{2 q + 1}$ $(4q - 3)/(2q + 1)$

How do you simplify 3q+22q+1+q−52q+1(3q+2)/(2q+1)+(q-5)/(2q+1)?