How do you simplify #(3a^4b^2)^3#?

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Answer 1 · 2017-10-24T11:01:53

#27a^12b^6#

Move the #3# inside by simply multiplying every power by #3#.

#(3a^4b^2)^3 = (3^1a^4b^2)^3#

#= (3^(1xx3)a^(4xx3)b^(2xx3))#

#= 3^3a^12b^6#

You can calculate #3^3# straight away, because

#3^3 = 3xx3xx3 = (3xx3)xx3 = 9xx3 = 27#

so

#(3a^4b^2)^3 = 27a^12b^6#