How do you simplify $3/(sqrt7-sqrt2)$ ?

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Answer 1 · 2018-07-19T02:36:15

$3/5(sqrt7+sqrt2)$

By rationalising the denominator which means that you multiply by the conjugate of your denominator

ie the denominator is $sqrt7-sqrt2$ so the conjugate of the denominator is $sqrt7+sqrt2$

$3/(sqrt7-sqrt2)$

= $3/(sqrt7-sqrt2)times(sqrt7+sqrt2)/(sqrt7+sqrt2)$

= $(3(sqrt7+sqrt2))/(7-2)$

= $3/5(sqrt7+sqrt2)$

How do you simplify 3/(sqrt7-sqrt2)3/(sqrt7-sqrt2)?