How do you simplify #(-3-sqrt2)/(3sqrt17)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Bill Jorgensen May 21, 2018 #(-9sqrt17-3sqrt(34))/(153)# Explanation: #(-3-sqrt2)/(3sqrt17)# you rationalize the denominator using: #(3sqrt17)/(3sqrt17) = 1# #(-3-sqrt2)/(3sqrt17)*(3sqrt17)/(3sqrt17)# #(-9sqrt17-3sqrt(34))/(3^2*(sqrt17)^2)# #(-9sqrt17-3sqrt(34))/(9*17)# #(-9sqrt17-3sqrt(34))/(153)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1273 views around the world You can reuse this answer Creative Commons License