How do you simplify $(3 + \sqrt{5}) (3 - \sqrt{5})$ $(3+sqrt 5)(3-sqrt 5)$ ?

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How do you simplify $(3 + \sqrt{5}) (3 - \sqrt{5})$ $(3+sqrt 5)(3-sqrt 5)$ ?

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Answer 1 · 2015-10-16T02:05:35

$(3 + \sqrt{5}) (3 - \sqrt{5}) = 4$ $(3+sqrt 5)(3-sqrt 5)=4$

Explanation:

$(3 + \sqrt{5}) (3 - \sqrt{5})$ $(3+sqrt 5)(3-sqrt 5)$

This is an example of the difference of squares, $(a^{2} - b^{2}) = (a + b) (a - b)$ $(a^2-b^2)=(a+b)(a-b)$ , where $a = 3 and b = \sqrt{5}$ $a=3 and b=sqrt5$ .

$(3^{2} - \sqrt{5^{2}}) =$ $(3^2-sqrt(5^2))=$

$9 - \sqrt{5^{2}}$ $9-sqrt(5^2)$

Apply the square root rule $\sqrt{x^{2}} = x$ $sqrt(x^2)=x$ .

$9 - 5 = 4$ $9-5=4$

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How do you simplify $(3 + \sqrt{5}) (3 - \sqrt{5})$ $(3+sqrt 5)(3-sqrt 5)$ ?

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How do you simplify (3+sqrt 5)(3-sqrt 5) (3+√5)(3−√5)(3+sqrt 5)(3-sqrt 5) ?

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How do you simplify $(3 + \sqrt{5}) (3 - \sqrt{5})$ $(3+sqrt 5)(3-sqrt 5)$ ?