How do you simplify $3 \sqrt{2} \cdot \times \cdot 5 \sqrt{10}$ $3 sqrt(2) times 5 sqrt(10)$ ?

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Answer 1 · 2017-10-21T08:57:14

$30 \sqrt{5}$ $30sqrt5$

$3 \sqrt{2} \times 5 \sqrt{10}$ $3sqrt2xx5sqrt10$

$= (3 \times 5) \sqrt{2} \times \sqrt{10} - - (1)$ $=(3xx5)sqrt2xxsqrt10--(1)$

$= 15 \sqrt{2 \times 10}$ $=15sqrt(2xx10)$

$= 15 \sqrt{20}$ $=15sqrt20$

$= 15 \sqrt{4 \times 5}$ $=15sqrt(4xx5)$

$15 \times \sqrt{4} \times \sqrt{5}$ $15xxsqrt4xxsqrt5$

$15 \times 2 \times \sqrt{5}$ $15xx2xxsqrt5$

$30 \sqrt{5}$ $30sqrt5$

at stage $(1)$ $(1)$ you could do

$(3 \times 5) \sqrt{2} \times \sqrt{2 \times 5}$ $(3xx5)sqrt2xxsqrt(2xx5)$

$= 15 \sqrt{2} \sqrt{2} \sqrt{5}$ $=15sqrt2sqrt2sqrt5$

$= 15 \times 2 \sqrt{5} = 30 \sqrt{5}$ $=15xx2sqrt5=30sqrt5$

How do you simplify 3√2⋅×⋅5√103 sqrt(2) *times* 5 sqrt(10)?