How do you simplify #3 sqrt(2) *times* 5 sqrt(10)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer sjc · Daniel L. Oct 21, 2017 #30sqrt5# Explanation: #3sqrt2xx5sqrt10# #=(3xx5)sqrt2xxsqrt10--(1)# #=15sqrt(2xx10)# #=15sqrt20# #=15sqrt(4xx5)# #15xxsqrt4xxsqrt5# #15xx2xxsqrt5# #30sqrt5# at stage #(1)# you could do #(3xx5)sqrt2xxsqrt(2xx5)# #=15sqrt2sqrt2sqrt5# #=15xx2sqrt5=30sqrt5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 6293 views around the world You can reuse this answer Creative Commons License