How do you simplify $(3 \sqrt{2} - \sqrt{5}) (2 \sqrt{5} + 4 \sqrt{2})$ $(3 sqrt 2-sqrt 5)(2 sqrt5+4 sqrt 2)$ ?

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Answer 1 · 2018-03-30T07:33:09

$14 +$ $14 +$ 2 $\sqrt{10}$ $sqrt10$

Expand the brackets
$(3 \sqrt{2} - \sqrt{5}) (2 \sqrt{5} + 4 \sqrt{2})$ $(3sqrt2 - sqrt5 )(2sqrt5 + 4sqrt2)$

= $6 \sqrt{10} + 12 \sqrt{4} - 2 \sqrt{25} - 4 \sqrt{10}$ $6sqrt10 + 12sqrt4 - 2sqrt25 - 4sqrt10$

Collect like terms and square root any square numbers;

= $2 \sqrt{10} + 24 - 10$ $2sqrt10 + 24 - 10$

= $2 \sqrt{10} + 14$ $2sqrt10 + 14$

Or

$14 + 2 \sqrt{10}$ $14 + 2sqrt10$

How do you simplify (3√2−√5)(2√5+4√2)(3 sqrt 2-sqrt 5)(2 sqrt5+4 sqrt 2)?