How do you simplify #3(a+3b+c)#? Algebra Properties of Real Numbers When to Use the Distributive Property 1 Answer smendyka Jan 23, 2017 To simplify multiply #color(red)(3)# by each term within the parenthesis: #color(red)(3)(a + 3b + c) -> (color(red)(3) xx a) + (color(red)(3) xx 3b) + (color(red)(3) xx c) -># #3a + 9b + 3c# Answer link Related questions How do you simplify #(9-6y)/3#? How do you simplify #\frac{10x+8y-1}{2# using the distributive property? How do you use the distributive property to simplify #- \frac{6z - 2}{3}#? How do you simplify #6 + (x - 5) + 7#? How do you use the distributive property to simplify #(r + 3)(-5)#? What is the student error if a student rewrote #4(9x + 10)# as #36x + 10# ? How do you use the distributive property to calculate #6(19.99)# in your head? When do you use the Distributive Property? How do you use the distributive property to multiply #6(3r+4s)#? How do you use the distributive property to simplify #79(101)#? See all questions in When to Use the Distributive Property Impact of this question 1439 views around the world You can reuse this answer Creative Commons License