How do you simplify #(3-3sqrt(3a))/(4sqrt(8a))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Evan Nov 17, 2017 #(3sqrt(2a))/(16a)-(3sqrt(6))/(16)# Explanation: #(3-3sqrt(3a))/(4sqrt(8a))# Multiply both denominator and numerator by #sqrt(8a)#, #(3-3sqrt(3a))/(4sqrt(8a))xx(sqrt(8a))/sqrt(8a)# #=(3sqrt(8a)-3sqrt(24a^2))/(32a)# #=(6sqrt(2a)-6asqrt(6))/(32a)# #=(3sqrt(2a)-3asqrt(6))/(16a)# #=(3sqrt(2a))/(16a)-(3sqrt(6))/(16)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2409 views around the world You can reuse this answer Creative Commons License