How do you simplify (3+ 2c ) ( 7- 4c )?

2 Answers
Jul 29, 2017

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(color(red)(3) + color(red)(2c))(color(blue)(7) - color(blue)(4c)) becomes:

(color(red)(3) xx color(blue)(7)) - (color(red)(3) xx color(blue)(4c)) + (color(red)(2c) xx color(blue)(7)) - (color(red)(2c) xx color(blue)(4c))

21 - 12c + 14c - 8c^2

We can now combine like terms:

21 + (-12 + 14)c - 8c^2

21 + 2c - 8c^2

Or in standard form:

-8c^2 + 2c + 21

Jul 29, 2017

21+2c-8c^2

Explanation:

"simplify means to multiply the factors together"

"each term in the second factor is multiplied by each term"
"in the first factor"

rArr(color(red)(3+2c))(7-4c)

=color(red)(3)(7-4c)color(red)(+2c)(7-4c)

"distributing the brackets gives"

=(color(red)(3)xx7)+(color(red)(3)xx-4c)+(color(red)(2c)xx7)+(color(red)(2c)xx-4c)

=21+(-12c)+14c+(-8c^2)

=21+2c-8c^2