How do you simplify $3 (2 - 3 x) + 3 (x - 4)$ $3(2-3x)+3(x-4)$ ?

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Answer 1 · 2016-12-13T14:29:10

$- 6 - 6 x$ $-6 - 6x$ or $- 6 (1 + x)$ $-6(1 + x)$

Step 1) Expand the terms within parenthesis:

$((3 \cdot 2) - (3 \cdot 3 x)) + ((3 \cdot x) - (3 \cdot 4))$ $((3*2) - (3*3x)) + ((3*x) - (3*4))$

$(6 - 9 x) + (3 x - 12)$ $(6 - 9x) + (3x - 12)$

$6 - 9 x + 3 x - 12$ $6 - 9x + 3x - 12$

Step 2) Group like terms:

$6 - 12 - 9 x + 3 x$ $6 - 12 - 9x + 3x$

Step 3) Combine like terms:

$- 6 + (- 9 + 3) x$ $-6 + (-9 + 3)x$

$- 6 + - 6 x$ $-6 + -6x$

$- 6 - 6 x$ $-6 - 6x$

or

$- 6 (1 + x)$ $-6(1 + x)$

How do you simplify 3(2-3x)+3(x-4)3(2−3x)+3(x−4)3(2-3x)+3(x-4)?