How do you simplify $[(2xy^3)^2]^3$ ?

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Answer 1 · 2017-01-19T01:24:35

$[(2xy^3)^2]^3=64x^6y^18$

We will use the following properties of exponents:

With those,

$[(2xy^3)^2]^3 = (2xy^3)^(2*3)$

$=(2xy^3)^6$

$=2^6x^6(y^3)^6$

$=2^6x^6y^(3*6)$

$=2^6x^6y^18$

$=64x^6y^18$

How do you simplify [(2xy^3)^2]^3[(2xy^3)^2]^3?