How do you simplify 2x+3/(x^2-9) + x/(x-3)?
1 Answer
Jan 11, 2018
Explanation:
"before adding the fractions we require them to have"
"a "color(blue)"common denominator"
"factorise the denominator "x^2-9
x^2-9=(x-3)(x+3)larrcolor(blue)"difference of squares"
"multiply numerator/denominator of"x/(x-3)" by "(x+3)
=3/((x-3)(x+3))+(x(x+3))/((x-3)(x+3))
"add the numerators leaving the denominator"
=(3+x^2+3x)/((x-3)(x+3))=(x^2+3x+3)/((x-3)(x+3))
