How do you simplify #(2x+1)(x-7)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Tony B Dec 14, 2015 #color(green)("A slightly different way of looking at how to solve it:")# #2x^2-13x-7# Explanation: Given: #color(brown)((color(blue)(2x+1))(x-7)# #color(brown)(color(blue)(2x)(x-7)color(blue)(+1)(x-7) # Consider each part: #color(brown)(color(blue)(2x)(x-7)) -> 2x^2-14x# #color(brown)(color(blue)(+1)(x-7)) ->+ x-7# Putting them together gives: #2x^2-14x+x-7# #2x^2-13x-7# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2818 views around the world You can reuse this answer Creative Commons License