How do you simplify $(2 x + 1) (x - 7)$ $(2x+1)(x-7)$ ?

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Answer 1 · 2015-12-14T16:23:20

$A slightly different way of looking at how to solve it:$ $color(green)("A slightly different way of looking at how to solve it:")$

$2 x^{2} - 13 x - 7$ $2x^2-13x-7$

Given: $(2 x + 1) (x - 7)$ $color(brown)((color(blue)(2x+1))(x-7)$

$2 x (x - 7) + 1 (x - 7)$ $color(brown)(color(blue)(2x)(x-7)color(blue)(+1)(x-7)$

Consider each part:

$2 x (x - 7) \to 2 x^{2} - 14 x$ $color(brown)(color(blue)(2x)(x-7)) -> 2x^2-14x$

$+ 1 (x - 7) \to + x - 7$ $color(brown)(color(blue)(+1)(x-7)) ->+ x-7$

Putting them together gives:

$2 x^{2} - 14 x + x - 7$ $2x^2-14x+x-7$

$2 x^{2} - 13 x - 7$ $2x^2-13x-7$

How do you simplify (2x+1)(x-7)(2x+1)(x−7)(2x+1)(x-7)?