How do you simplify $(- 2 w^{- 2}) (- 3 w^{2} b^{- 2}) (- 5 b^{- 3})$ $(-2w^-2)(-3w^2b^-2)(-5b^-3)$ ?

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Answer 1 · 2015-06-22T11:33:08

$= - 30 b^{- 5}$ $=color(blue)(-30b^-5$

Here all terms within brackets need to be multiplied:

Rearranging the terms
$(- 2 . - 3 . - 5) (w^{- 2} . w^{2}) (. b^{- 2} b^{- 3})$ $(-2. -3 . -5)(w^-2 . w^2)(.b^-2b^-3)$

Note: $a^{m} . a^{n} = a^{m + n}$ $color(blue)(a^m.a^n = a^(m+n)$

Applying the above property to the exponents of $w$ $w$ and $b$ $b$

$= - 30 . w^{(- 2 + 2)} . b^{(- 2 - 3)}$ $=-30.w^color(blue)((-2 +2)).b^color(blue)((-2-3)$
$= - 30 w^{0} b^{- 5}$ $=-30w^0b^-5$

Note: $a^{0} = 1$ $color(blue)(a^0 = 1$
$= - 30 b^{- 5}$ $=color(blue)(-30b^-5$

How do you simplify (-2w^-2)(-3w^2b^-2)(-5b^-3) (−2w−2)(−3w2b−2)(−5b−3)(-2w^-2)(-3w^2b^-2)(-5b^-3) ?