How do you simplify #2sqrt5(3+sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 13, 2015 The Distributive Property of Multiplication tells us that #color(blue)(a*(b + c ) = a*b + a* c # #color(red)(2sqrt5(3+sqrt2)# # = (2sqrt5)*3+(2sqrt5)*sqrt2# # = 6sqrt5+2(sqrt5*sqrt2)# # = 6sqrt5+2(sqrt(5*2))# (Because #color(blue)(sqrta*sqrtb = sqrt(a*b)# # color(green)(= 6sqrt5+2sqrt(10)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1246 views around the world You can reuse this answer Creative Commons License