How do you simplify #(2sqrt5)/(2sqrt7+3sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer 건 최. Oct 8, 2017 #(4sqrt(35)-6sqrt(15))# Explanation: #(2sqrt(5))/(2sqrt(7)+3sqrt(3))=(2sqrt(5))/(sqrt(28)+sqrt(27))=((2sqrt(5))(sqrt(28)-sqrt(27)))/((sqrt(28)+sqrt(27))(sqrt(28)-sqrt(27)))=(4sqrt(35)-6sqrt(15))/1=(4sqrt(35)-6sqrt(15))# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1349 views around the world You can reuse this answer Creative Commons License