How do you simplify $(2sqrt4)/(8sqrt3)$ ?

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Answer 1 · 2016-09-04T03:26:48

$sqrt3/6$

$(2sqrt4)/(8sqrt3) = (2xx2)/(8sqrt3) = 1/(2sqrt3)$

$1/(2sqrt3)xxsqrt3/sqrt3 = sqrt3/(2xx3) =sqrt3/6$

Answer 2 · 2016-09-04T07:42:31

$(sqrt(3)) / (6)$

We have: $(2 sqrt(4)) / (8 sqrt(3))$

$= (2 cdot 2) / (8 sqrt(3))$

$= (4) / (8 sqrt(3))$

$= (1) / (2 sqrt(3))$

Now, let's rationalise the denominator by multiplying both the numerator and denominator by $sqrt(3)$ :

$= (1) / (2 sqrt(3)) cdot (sqrt(3)) / (sqrt(3))$

$= (sqrt(3)) / (2 cdot 3)$

$= (sqrt(3)) / (6)$

How do you simplify (2sqrt4)/(8sqrt3)(2sqrt4)/(8sqrt3)?