How do you simplify #2sqrt3(5sqrt3 + 5sqrt5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan N. Nov 1, 2017 Expression #=10(3+sqrt15 ) approx 68.72983# Explanation: Expression #= 2sqrt3(5sqrt3+5sqrt5)# Expand; #= 10xxsqrt3xxsqrt3 + 10xx sqrt3xxsqrt5# #= 10xx3 + 10xx sqrt15# #=10(3+sqrt15)# #approx 68.72983# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 942 views around the world You can reuse this answer Creative Commons License