How do you simplify $2 \sqrt{3} \cdot 4 \sqrt{2}$ $2sqrt3 * 4sqrt2$ ?

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Answer 1 · 2018-03-10T22:01:01

$8 \sqrt{6}$ $8sqrt6$

$2 \sqrt{3} \cdot 4 \sqrt{2} = (2 \cdot 4) \cdot (\sqrt{3} \cdot \sqrt{2})$ $2sqrt3 * 4sqrt2 = (2*4) * (sqrt3 * sqrt2)$

$\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ $sqrta * sqrtb = sqrt(a*b)$ (law of indices)

$\sqrt{3} \cdot \sqrt{2} = \sqrt{6}$ $sqrt3 * sqrt2 = sqrt6$

$2 \cdot 4 = 8$ $2 * 4 = 8$

$2 \sqrt{3} \cdot 4 \sqrt{2} = 8 \sqrt{6}$ $2sqrt3 * 4sqrt2 = 8sqrt6$

How do you simplify 2√3⋅4√22sqrt3 * 4sqrt2?