How do you simplify #(-2sqrt3+2)(sqrt3-5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Barney V. Jul 22, 2017 #color(magenta)(4(3sqrt3-4)# Explanation: #(-2sqrt3+2)(sqrt3-5)# #:.sqrt3 xx sqrt3=3# #:.-2 xx sqrt3 xx sqrt3=-6# #:.2sqrt3+10sqrt3=12sqrt3# #:.-5 xx 2=-10# #:.-6+(12sqrt3)+(-10)# #:.=12sqrt3-16# #:color(magenta)(.=4(3sqrt3-4)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1180 views around the world You can reuse this answer Creative Commons License