How do you simplify #2log_5 12-log_5 8-2log_5 3#?

1 Answer
Noah G
Nov 10, 2016

This simplifies to #log_5(2)#.

Explanation:

Use the rule #alogn = logn^a# to get rid of the coefficients.

#=>log_5(144) - log_5(8) - log_5(9)#

Next, use the rule #log_a(n) - log_a(m) = log_a(n/m)#.

#=>log_5((144/8)/9)#

#=>log_5(2)#

Hopefully this helps!

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