How do you simplify $2/(sqrt3-2)$ ?

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Answer 1 · 2016-03-10T17:52:55

$-(4+2sqrt3)$

$2/(sqrt3-2$
$=(2(sqrt3+2))/((sqrt3-2)(sqrt3+2))$
$=(2(sqrt3+2))/((sqrt3)^2-2^2)$
$=(2(sqrt3+2))/(3-4)$
$-(4+2sqrt3)$

How do you simplify 2/(sqrt3-2)2/(sqrt3-2)?