How do you simplify $2 \sqrt{8}$ $2 sqrt 8$ ?

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How do you simplify $2 \sqrt{8}$ $2 sqrt 8$ ?

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Answer 1 · 2016-04-04T15:14:56

$4 \sqrt{2}$ $4sqrt2$

Explanation:

Using the following $rules of radicals$ $color(blue)" rules of radicals "$

$\sqrt{a} b = \sqrt{a} \times \sqrt{b} \Leftrightarrow \sqrt{a} \times \sqrt{b} = \sqrt{a} b$ $sqrtab = sqrtaxxsqrtb hArr sqrtaxxsqrtb = sqrtab$

$\sqrt{8} can be written \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}$ $sqrt8" can be written " sqrt(4xx2) = sqrt4xxsqrt2 = 2sqrt2$

$\Rightarrow 2 \sqrt{8} = 2 \times 2 \times \sqrt{2} = 4 \times \sqrt{2} = 4 \sqrt{2}$ $rArr 2sqrt8 = 2xx2xxsqrt2 = 4xxsqrt2 = 4sqrt2$

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