How do you simplify #(2 sqrt 3+1) (sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Aswin K. Aug 15, 2017 See the explanation process Explanation: #(2sqrt3+1)(sqrt3)# #(a+b)*c=>a*c+b*c,# Apply this #=>(2sqrt3+1)(sqrt3)# #=>(2sqrt3*sqrt3)+(1*sqrt3)# #=>(2*sqrt3*sqrt3)+sqrt3# #=>(2*3)+sqrt3# #=>6+sqrt3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2519 views around the world You can reuse this answer Creative Commons License