How do you simplify #(-2^5)(7^-10)#?

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Answer 1 · 2017-06-03T18:59:00

See a solution process below:

The negative exponent can be eliminated using this rule for exponents:

#x^color(red)(a) = 1/x^color(red)(-a)#

#(-2^5)(7^color(red)(-10)) => (-2^5)(1/7^color(red)(- -10)) =>#

#(-2^5)(1/7^color(red)(10)) => -2^5/7^10#

Or

#-32/(282,475,249)#