How do you simplify 2/(4-sqrt6)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Konstantinos Michailidis Apr 24, 2016 It is 2/(4-sqrt6)=[2*(4+sqrt6)]/[(4-sqrt6)*(4+sqrt6)]= [2*(4+sqrt6)]/(4^2-(sqrt6)^2)= 2*(4+sqrt6)/[16-6]=2/10*(4+sqrt6)=1/5*(4+sqrt6) Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1618 views around the world You can reuse this answer Creative Commons License