How do you simplify $\frac{2}{3 \sqrt{63}}$ $2/(3sqrt63)$ ?

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Answer 1 · 2018-03-18T10:32:54

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We need to rationalise the denominator, in this case multiply both numerator and denominator by $\sqrt{63}$ $sqrt(63)$

$\Rightarrow \frac{2}{3 \sqrt{63}} \cdot \frac{\sqrt{63}}{\sqrt{63}}$ $=> 2/( 3sqrt(63) ) * sqrt(63) / sqrt(63)$

$\Rightarrow \frac{2 \sqrt{63}}{3 \cdot 63}$ $=> ( 2sqrt(63) ) /( 3 * 63)$

$\Rightarrow \frac{2 \cdot \sqrt{3 \cdot 3 \cdot 7}}{189}$ $=>( 2 * sqrt(3*3* 7 ) ) / 189$

$\Rightarrow \frac{6 \sqrt{7}}{189}$ $=> ( 6sqrt(7) ) / 189$

$\Rightarrow \frac{2 \sqrt{7}}{63}$ $=> (2sqrt(7) ) / 63$

Answer 2 · 2018-03-18T10:49:24

$\frac{2 \sqrt{7}}{63}$ $(2 sqrt7)/63$

$\frac{2}{3 \sqrt{63}}$ $2/(3sqrt63)$

$:.=2/(3sqrt(3*3*7))$

$:.sqrt3*sqrt3=3$

$:.=2/(3*3sqrt7)$

$:.=2/(9sqrt7)$

$:.=2/(9sqrt7)xxsqrt7/sqrt7$

$:.sqrt7xxsqrt7=7$

$:.=(2sqrt7)/(9xx7)$

$:.=(2sqrt7)/63$

How do you simplify 2/(3sqrt63) 23√632/(3sqrt63) ?