How do you simplify $\frac{2}{3 - \sqrt{3 x^{2}}}$ $2/(3-sqrt(3x^2))$ ?

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Answer 1 · 2018-01-28T11:11:52

$\frac{2 (3 + \sqrt{3} \cdot x)}{3 (3 - x^{2})}$ $(2(3+sqrt3 *x)) /(3(3- x^2))$

$\frac{2}{3 - \sqrt{3 x^{2}}} = \frac{2}{3 - \sqrt{3} \cdot x}$ $2/(3-sqrt(3x^2))= 2/(3-sqrt3 *x)$ . Multiplying both numerator

and denominator by $(3 + \sqrt{3} \cdot x)$ $(3+sqrt3 *x)$ we get ,

$\frac{2 (3 + \sqrt{3} \cdot x)}{(3 - \sqrt{3} \cdot x) (3 + \sqrt{3} \cdot x)}$ $(2(3+sqrt3 *x)) /((3-sqrt3 *x)(3+sqrt3 *x))$

$= \frac{2 (3 + \sqrt{3} \cdot x)}{3^{2} - {(\sqrt{3} \cdot x)}^{2}}$ $=(2(3+sqrt3 *x)) /(3^2- (sqrt3 *x)^2)$

$= \frac{2 (3 + \sqrt{3} \cdot x)}{9 - 3 \cdot x^{2}}$ $=(2(3+sqrt3 *x)) /(9- 3 *x^2)$

$= \frac{2 (3 + \sqrt{3} \cdot x)}{3 (3 - x^{2})}$ $=(2(3+sqrt3 *x)) /(3(3- x^2))$ [Ans]

How do you simplify 23−√3x22/(3-sqrt(3x^2))?