How do you simplify #(2^2)^2*(2^3)^-1# and write it using only positive exponents?

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Answer 1 · 2017-04-11T16:39:14

I found #2#

We can use some properties of exponents and write it as:
#2^(2*2)/2^3=2^4/2^3=2#

Where we used the following:
#(x^a)^b=x^(a*b)#
and
#x^-a=1/x^a#

Answer 2 · 2017-04-11T16:39:32

#2#

#(2^2)^2*(2^3)^-1#

#:.=(2*2)*(2*2)*(2*2*2)^(-1)#

#:.=4*4*8^-1#

#:.=16*1/8#

#:.=16/8#

#:.=2#