How do you simplify #18 / sqrt3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Jun 24, 2016 #6sqrt(3)# Explanation: Multiply by 1 but in the form of #1=sqrt(3)/sqrt(3)# #color(brown)("Multiplying by 1 does not change the inherent value but it can")##color(brown)("change the way something looks.")# #18/sqrt(3)xxsqrt(3)/sqrt(3)# #(cancel(18)^6xxsqrt(3))/(cancel(3)^1)" "=" "6sqrt(3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1216 views around the world You can reuse this answer Creative Commons License