How do you simplify $\frac{16 \sqrt{21}}{2 \sqrt{7}}$ $(16sqrt21) / (2sqrt7)$ ?

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How do you simplify $\frac{16 \sqrt{21}}{2 \sqrt{7}}$ $(16sqrt21) / (2sqrt7)$ ?

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Answer 1 · 2018-05-09T10:26:26

$8 \sqrt{3}$ $8sqrt3$

Explanation:

$using the law of radicals$ $"using the "color(blue)"law of radicals"$

$∙ x \frac{\sqrt{a}}{\sqrt{b}} \Leftrightarrow \sqrt{\frac{a}{b}}$ $•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)$

$\Rightarrow \frac{16}{2} \times \frac{\sqrt{21}}{\sqrt{7}} = 8 \times \sqrt{\frac{21}{7}} = 8 \sqrt{3}$ $rArr16/2xxsqrt21/sqrt7=8xxsqrt(21/7)=8sqrt3$

Answer 2 · 2018-05-09T10:43:00

$\frac{16 \sqrt{21}}{2 \sqrt{7}} = 13.856$ $(16sqrt21)/(2sqrt7)=13.856$

Explanation:

Given -

$\frac{16 \sqrt{21}}{2 \sqrt{7}}$ $(16sqrt21)/(2sqrt7)$

$\frac{16}{2} \times \frac{\sqrt{21}}{\sqrt{7}}$ $16/2xxsqrt21/sqrt7$

$\frac{16}{2} \times \frac{{(\sqrt{21})}^{2}}{{(\sqrt{7})}^{2}}$ $16/2xx(sqrt21)^2/(sqrt7)^2$

$\frac{16}{2} \times \frac{21}{7}$ $16/2xx21/7$

$8 \times \sqrt{3} = 8 \times 1.732 = 13.856$ $8xxsqrt3=8 xx 1.732=13.856$

$\frac{16 \sqrt{21}}{2 \sqrt{7}} = 13.856$ $(16sqrt21)/(2sqrt7)=13.856$

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How do you simplify $\frac{16 \sqrt{21}}{2 \sqrt{7}}$ $(16sqrt21) / (2sqrt7)$ ?

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