How do you simplify #(15-sqrt75)/5#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Sep 7, 2016 #3-sqrt(3)# Explanation: Given:#" "(15-sqrt(75))/5# #15 -> 3xx5# #75->3xx25 -> 3xx5^2# Write as: #((3xx5)-sqrt(3xx5^2))/5# #((3xx5)-5sqrt(3))/5# #(5(3-sqrt(3)))/5# #3-sqrt(3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1033 views around the world You can reuse this answer Creative Commons License