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How do you simplify #(-10i)(-9i)-(8i)(6+9i)#?

1 Answer

Oct 10, 2016

#(-10i)xx(-9i)-8i(6+9i)=-18-48i#

Explanation:

#(-10i)xx(-9i)-8i(6+9i)= (-9xx-10)i^2-48i-72i^2#

And so, #(-9xx-10)i^2-48i-72i^2#

#=# #18i^2-48i#

Of course, we know that #i^2=-1#

Thus, #18i^2-48i#

#=# #-18-48i#

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