How do you simplify $(1 - \sqrt{3}) (3 + \sqrt{2})$ $(1-sqrt3) (3+ sqrt2)$ ?

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Answer 1 · 2016-02-07T09:19:30

$3 + \sqrt{2} - 3 \sqrt{3} - \sqrt{6}$ $3+sqrt2-3sqrt3-sqrt6$

Use the FOIL method of multiplying Binomials:
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$(1 - \sqrt{3}) (3 + \sqrt{2})$ $(1-sqrt3)(3+sqrt2)$

$ul Firsts$

$rarr=1*3=3$

$ul Outer$

$rarr=1*sqrt2=sqrt2$

$ul I$ $n$ $n$ $er$

$rarr=-sqrt3*3=-3sqrt3$

$ul L$ $a$ $st$

$rarr=-sqrt3*sqrt2=-sqrt6$

Now put them all together:

$(1-sqrt3)(3+sqrt2)=3+sqrt2-3sqrt3-sqrt6$

How do you simplify (1-sqrt3) (3+ sqrt2)(1−√3)(3+√2)(1-sqrt3) (3+ sqrt2)?