How do you simplify #(1-7i)^2#?

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Answer 1 · 2016-10-25T17:28:18

#=(1 - 7i)(1 - 7i)#

#=1 - 7i - 7i + 49i^2#

We know that #i^2 = -1#, so:

#=1 - 14i + 49(-1)#

#=1 - 14i - 49#

#=-48 - 14i#

Hopefully this helps!